An object is 4 cm high and is located 17 cm in front of a thin converging lens with a focal length of 12 cm.
a. Calculate the position (distance from the center of the lens) of the image.
b. Calculate the image height (including sign).
Use the thin lens equation to solve problems 14 –18. 14. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 15. An object is 10 cm high and is placed 16 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 16. An object is...
(2) An object is located at a distance of 4 cm from a thin converging lens with focal length of 2 cm. A diverging lens is located 3 cm from the converging lens and 7 cm from the object. The diverging lens has a focal length of -2 cm. Use the thin lens equation to predict the following (a) Location of the final image? to the object? (c) Is the final image real or virtual?
An object is located at a distance of 6 cm from a thin converging lens with focal length of 2 cm. A diverging lens is located 4 cm from the converging lens and 10 cm from the object. The diverging lens has a focal length of -3 cm. Note: To handle a multiple lens system, we treat them independently. We first find the image created by the first lens. We then use the image from the first lens to act...
Use ray diagrams to solve problems 10 –13. 10. An object is 10 cm high and is placed 30 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 11. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 12. An object is 10 cm...
Problem 1: Ray tracing with a converging lens A 17 cm high object is located 50 cm away from a converging lens with a focal length of 30 cm. The drawing below is to scale (but is not necessarily at a scale of 1:1). A. Draw a ray diagram to find the image, including the height and orientation of the image: you only need to draw 2 of the special rays, but you can draw more if you'd like. Use...
An object is on the left side of a thin converging lens. The object is located at a distance of 6 cm away from a thin converging lens with focal length of 2 cm. Use the thin lens equation (1/f = 1/s' + 1/s) to predict the following: (a) Location of the image? (b) Magnification of the image (including inverted versus non-inverted)? (c) Real or virtual? Draw diagram please!
Problem 4 (10 points) A thin converging lens has a focal length 6.0 cm. An object of height 2.0 cm is located 3cm in front of the lens as shown below 1) Draw a ray diagram to show the image position and size. 2) Calculate the image position and size using lens equations. -6em, 4em h-2cm f-6cm f-6cm s 3cm
webassign.net Active Figure 26.25 Thin Lenses The animation below shows a thin lens, an object (blue arrow) and an image (tan arrow). Three rays are shown that locate the positic orientation, and size of the image. Readouts are provided for object distance, object height, image distance and image height. Instructions: Click and drag the blue object. Click the button in the lower left of the applet window to toggle between a conc convex lens. Explore Images formed by thin lenses...
A 20 cm high object is located 50 cm from a +20 cm focal length converging lens. a) Find the image distance. b) Find the magnification. c) Find the image height. d) Describe the image,
A 20 cm high object is located 50 cm from a +20 cm focal length converging lens. a) Find the image distance. b) Find the magnification. c) Find the image height. d) Describe the image,