Question

Question 5 (6 points) which one of the following combinations of entropy and enthalpy would cause a process or reaction to be nons at all temperatures given the free energy formula shown below. 0 a) as < 0 (-) and ΔΗ > O (+) b) as > 0 (+) and ΔΗ > O (+) @c)as>0(+) and ΔΗ < 0(-) d) AS >0(+) and AH >0(+) Question 6 (6 points) For all spontaneous processes or reactions the value of free energy(AG) will be

Answer 1

Q5. Correct option is : (a) $\dpi{100} \small \Delta$ S < 0 (-) and $\dpi{100} \small \Delta$ H > 0 (+)

Q6. For all spontaneous processes or reactions the value of free energy($\dpi{100} \small \Delta$G) will be negative

Q10. Correct option is : (d) Ag⁺

Explanation

Q5. For the reaction to be non-spontaneous at all temperatures, both terms $\dpi{100} \small \Delta$ H and -T$\dpi{100} \small \Delta$S should be positive. This is only possible when $\dpi{100} \small \Delta$ H is positive and $\dpi{100} \small \Delta$ S is negative (so that -T$\dpi{100} \small \Delta$S becomes positive).

When both terms are positive at all temperatures, the value of $\dpi{100} \small \Delta$ G will be positive at all temperatures and reaction will be non-spontaneous.