roll a pair of fair dice. find the expected sum, given that at least one of...
8. We roll two fair dice. (1) Given that the roll results in a sum of 6 or less, what is the conditional probability that doubles are rolled? A "double" means that two dice have the same number (2) Given that the two dice land on different numbers, what is the conditional proba- bility that at least one die roll is a 1?
.1. A pair of fair dice is thrown, what is the probability that the sum of the two numbers is greater than 10. 2. A pair of fair dice is thrown. Find the probability that the sum is 9 or greater if a. If a 6 appears on the first die. b. If a 6 appears on at least one of the dice.
Suppose you roll a pair of fair 6-sided dice and place a bet on the sum. Which number would you select? (justify!)
Find the conditional probability, in a single roll of two fair 6-sided dice, that the sum is less than 6, given that the sum is even The probability is 2 (Type an integer or a simplified fraction) 1
3) We roll 2 fair dice. a) Find the probabilities of getting each possible sum (i.e. find Pr(2), Pr(3), . Pr(12) ) b) Find the probability of getting a sum of 3 or 4 (i.e.find Pr(3 or 4)) c) Find the probability we roll doubles (both dice show the same value). d) Find the probability that we roll a sum of 8 or doubles (both dice show the same value). e) Is it more likely that we get a sum...
(2) If we roll a pair dice, what is the probability that: (a) the sum is 8? (b) both are 3 providing that one of them is 3?
roll a pair of dice and let I=1 if the sum is 7 and I=0 if sum is others. find the variance of I.
A dice game is played with two distinct 12 sided dice. It costs $3 to roll the pair of dice one time. The payout scheme is as follows 1. Sum of 13 pays $10 Sum of 11 or 15 pays $6 Sum of 7, 9, 17, or 19 pays $3 Any other roll doesn't pay. What is the expected gain/loss after playing the game one time? A "fair" game is one in which the expected gain/loss after playing once is...
Roll 10 dice. Find probability sum of dice is 42. (dice are 6-sided. Min roll = 10. Max roll = 120.) (number of possible rolls = 6^10 = 60466176) = s^n number of favorable rolls = number of ways dice add to 42 [(number of favorable rolls)/(number of possible rolls)] = [Probability sum is 42] You must find number of favorable rolls. Given number of dice(n), sides(s), and sum of roll (r) as n = 10, s = 6, and...
if you have two fair dice that are rolled, what is the probability of a sum 6 given that the roll is a 'double'?