need help on all parts (10%) Problem 7: With the aid of a string, a gyroscope...

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(10%) Problem 7: With the aid of a string, a gyroscope is accelerated from rest to 33 rad/s in 0.38 s. Randomized Variables =

Answer 1

Answer #1

(a) from the kinematics of rotational motion

wf = wi + alpha x t;

plugging the values in the equation

33 = 0 + alpha x 0.38;

angular acceleration, alpha = 33/0.38;

= 86.842 rad/s²

(b) from the kinematics of rotational motion

theta = wi x t + 0.5 x alpha x t²

= 0 + 0.5 x 86.842 x 0.38²

= 6.26999 rad

now the number of revolutions n = 6.26999/(2pi);

n = 0.9979 revolutions.

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Answer 2

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