Question

Question 1 2 pts With the aid of a string, a gyroscope is accelerated from rest to 32 rad/s in 0.40 s. What is its angular acceleration in rad/s?? Question 2 2 pts How many revolutions does it go through in the process?

Answer 1

STA RTS FROM REST * DATA:- 0) (wo)=(0: Smets FROM REST) (wuf )={32 vad ſec] (t) = (64 sec ) (0) = ? (in radls2) solen

By kinematics ootational), we have, where (vo) = initial angular- caup)-(wotat) l velocity Here, Evo)= (6) (t) = 04 sec) (W f )=(32 vad (see) Ewf = final angular- Luelocity J (t)=(time tastien Carangular - 7 Lacceleration /

.: (012) (a)= Curs van . (1)=) del wuf-wo sec sec S2 60= 80oad lis angeslax acceleration of gyroscope.

here, By kinematics (oofafionar), we have, I where Cuf - wố )= 240) 5360(wo) = (initia) angular-2 I velocity J (CMO) = C) wuf jlfinal angular-1 l velocity Wwf )=(32 dad /sec) (2)=(angular (0)=(80 gadis2) [ acceleration / (O) = ? (0)= angular- { displacement

20 .: (=) (6)= feugiat - [ Caz sad seeg? (0327 2(80) padla revolutions? : (hoew)= (27T vadians) 7 J - loads = [Com Joevolutions? | (Trevolution) .:O)=(svevolution) is undergone by gyroscope in this process.

* conclusions- *(1) (2)=(so sad se] *® (@) = (Irevolution)