With the aid of a string, a gyroscope is accelerated from rest to 40 rad/s in 0.40 s under a constant angular acceleration. (a) What is its angular acceleration in rad/s²? (b) How many revolutions does it go through in the process?
a. 16 ra d.ls2 ana 0.2 rev
b. 16 radls2 and 0.4 rev
c. 100 rad/s2 and 0.7 rev
,d. 100 radls2 and 1.3 rev
Apply rotational kinematic equation
wf- wi = alpha t
alpha = 40-0/0.40
=100 rad/s^2
theta = 1/2 * alpha t^2
= 1/2 * 100 (0.4)^2
= 8 rad ( 1 rev/ 2 pi rad) = 1.3 rev
option (d) is correct answer
With the aid of a string, a gyroscope is accelerated from rest to 40 rad/s in...
With aid of a string, a gyroscope is accelerated from rest to 40 rad/s in 0.40s. What is its angular acceleration in rad/s^2? How many revolutions does it go through in the process? a. 16 rad/s^2 and 0.2 rev b. 16 rad/s^2 and 0.4 rev c. 100 rad/s^2 and 0.7 rev d. 100 rad/s^2 and 1.3 rev
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