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Suppose that 22.65 mL of a 0.02024 M permanganate solution was needed to react with the...

Suppose that 22.65 mL of a 0.02024 M permanganate solution was needed to react with the Fe^2+ in a sample that had a mass of 1.1243 g. What is the mass of the Fe^2+ in the sample and what is the % of Fe^2+ in the sample?

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Answer #1

Mno45 Fe2+8 H+ Mn2+5 Fe34 H20 Moles of Mn04-= volume x concentration of KMnO4 -22.65/1000 x 0.020240.000458436 mol Moles of F

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