3 Draw the circuit at too and force i(0*) and ve(0*). Then solve for v(0*) and...
2.0 Prelab Questions (40 polnts) You will have to solve for the circuit, run PSPICE simulation and plot your solution using Matlab simulation prior coming to the lab. a) For the circuit of Figure 3, let R, 4700, R2 470 n, C- 100nF and L= 1mH. Include the 500 internal source resistance for more accuracy. Solve for the step response for (t) and velt) fort>0 after adding the 5V. (10 points) ges st is e laton betueen Ve Function Generator...
Function Generator L =1 mH t-0 R 20 Rs 500 R 4700 R2 Vc 4700 + Rsense 101 100 ------ www For the circuit of Figure 3, let R1 4700n, R2 = 470n, c= 1 nF and L 1mH. Include the 50 0 internal source resistance for more accuracy. Solve for the step response I(t) and ve(t) for t > 0 after adding the 5V. (10 points)
Solve all the problems shown below Problem 1 In a source free RLC series circuit If R=1092 ,L=5H ,and C= 2 mF 1) Find a.,0, and the characteristics roots $,$2. 2) Find the response i(t) knowing that v(0)=5V and i(0)=1A Problem 2 In a source free RLC parallel circuit If R=52 ,L= 1H ,and C= 10 m 1) Find a ,0, and the characteristics roots S1,S2. 2) Find the response V(t) knowing that v(O)=10V and i(0)=5A Problem 3 In a...
Function Generatr Inductor Model Ra R, Figure 1 Series RLC Circuit Preliminary This laboratory will demonstrate how varying resistance changes the natural response of a series RLC circuit (Fig. 1). The function generator is modeled as an ideal voltage source v(t) 5 u() V in series with source resistance Rs-50Q. After measurements using an LCR meter, the inductor is modeled as an ideal L 90 mH inductor in series with resistance RL-20Q. The capacitance is C-0.22 μF. 1) Calculate the...
need help on some review of a RLC circuit.
better?
thats the part i need help on
fig. a lice c Vekt) A vet) R=4002 =1,274 c=1.25 uf lert fig. b A sea venting switching 2nd order ckt can be modled when the gate function Shown in fy b is applied to the parallel LLC ckt shown in Fig a Veo)=5v & i (o)=0A a.) find b.) find ilt) & vlts for oftasoms ilsoms), visoms), & dils & dicsoms) c.)...
Problem # 3 (20 pts.) A) Given For the circuit IL (t) I() (T Let R-2Ω, L-05H, C = .05F. Also Vo(0) = 0 Volts, and L(0) = 0 Amps B) Determine 1) The transfer function Vc(s)/I(s) 2) The pole-zero map 3) The response Vo(t) if I(t)-6(t)A (impulse response) 4) The response Vc(t) if l(t)u(t)A (step response) 5) The step response plot using MATLAB (optional) Evaluation Criteria Rubric for Problem # 3 Activities Step 1) Step 2 Step 3) Step...
Given i(t) 3e2 A, find vc(1) for the circuit shown in Figure 7.3. 10 92 i(t) Velt)1/5 F Figure 7.3 Velt)- 30e2 v
Given i(t) 3e2 A, find vc(1) for the circuit shown in Figure 7.3. 10 92 i(t) Velt)1/5 F Figure 7.3 Velt)- 30e2 v
3. RLC Parallel Circuit a) (7pts) For the circuit shown, determine the ODE relating the voltage (t) to the current source is(t) as well as the > L corresponding transfer function z(s) = (Hint: It might be easier to find the latter before the former.] (12pts) For R-0.802, C=0.25F and L=1H, determine the (1) impulse response, (ii) the unit step response and (111) the response to a pure sinusoid is (t) = cos(itt) Amperes (note that this last function is...
Problem 1 (Problem Solving Workshop 1) For a parallel RL circuit R-10, L 1H Determine 1) 21 3) 4) The transfer function H(s) = (s), the pole-zero map, and the step response. Let L(0) - OA The state and output equations. Let Lt) be the state variable The block diagram of this system. Let (O) = -1 The response (t) due to a step input (t) = (t) A) using a known software. Problem #2 (Problem Solving Workshop 1) For...
find response of the parallel RLC circuit on Figure 3. Sketch iL(t)
for tE( 0, 50us)
initial voltage on the capacitor Vo = 10v.
initial current in the inductor is 100mA.
current source is 100mA.
(Please order all steps so I know how to approach a problem
like this)
Find response of the Parallel RLC circuit on Figure 3. Sketch iz(t) fort € (0, 50uS) Initial Voltage on the capacitor Vo=10V Initial curent in the inductor is 100mA Current Source...