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dSsurroundings...
so..
S = Q/T since Q = -HRxn of system
so
Q = 906 kJ
T = 25°C = 298K
therefore
S surroundings = (906*10^3)/(298) =3040.268 J/molK
so..
S surroundings 3. 04 kJ/mnolK
choose B
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Determine the entropy change in the surroundings for the following reaction at 25.0 degree C:...
Use the standard reaction enthalpies given below to determine Delta H_rxn degree for the following reaction:...
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For the following reaction at 25.0 degree C, 2 C(s) + O_2(g) rightarrow 2 CO(g) calculate Delta S degree_univ given Delta S degree_sys = 179.1 J/K and Delta H degree_sys = -221.1 kJ.
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