For Question 1, you can understand the concept through Venn- Diagram as well as through the given equation. Now, it is given that
Method-1
NA=NAB+ NABc
NA - NAB = NABc ............(1)
Also, Probability for ABc, P(ABc) = NABc / N, where N are the total number of trials.
Also, from dividng equation 1 by N we get
NA / N - NAB/ N = NABc /N
P(A) - P(AB) = P(ABc)
Hence, proved !
Method-2 By Venn Diagram
Now, ABc refers to the region which is obtained by A and excluding B. Thus, it can be shown as,
Now, this region can also be referred as or AB removed from A. Thus A - .
Therefore, P(A) - P(AB) = P(ABc)
hlep me to slove this question Exercice 1 If A and B are not mutually exclusive...
Question 5 1 pts If A and B are mutually exclusive events, then P(AB) = P(AUB) Not enough information to answer the question O False O True
Question 1 1 pts Suppose A and B are mutually exclusive events in a sample space S with probabilities P(A) - 0.22 and P(B) = 0.39 respectively. What is the probability that either A or B occurs? (Round the value to the 2-nd decimal place) 0.39 0.61 0.0 Not enough information to answer the question 0.48 0.52 O 0.70
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