Question

Part 1 out of 2 Your B-cells can produce millions of different types of immunoglobulins (antibodies) even though here are only about 200 genes encoding the different parts of an antibody. The light chains of an antibody are assembled by joining a variable segment, a joining segment, and a constant segment from a single immunoglobulin gene. Gene rearrangement within an immunoglobulin gene brings together one of forty different variable segments with one of four different joining segments, and the single constant region of an immunoglobulin gene. How many different light chain variations could be made assuming that an immunoglobulin gene had 19 variable segments, 2 joining segments, and one constant region? light chain variations 3 attempts len Check my work Next part

Answer 1

Combinatorial diversity at light chain is = total number of variable segments x total number of joining segments

= 19 x 2 = 38

Therefore total 38 light chain variations are possible