Question

A production process Kenneth Day Manufacturing is shown in the rebelow. Thengertion go through only one of the three assembly operations (the operations are in parte tod a y the wing and wegende Aroute to round your The botenecke mi t The Proughout time of the overall system a n d you to be

Answer 1

Answer a)

Step 1: Here, first, find the time taken (in minutes) for processing a unit, for all the work stations as mentioned below:

Processing Time (In Minutes) = 60 Minutes / Units Processed in an Hour

Hence, processing time at workstation:

1) Sawing = 60 / 7 = 8.5714 Min / Unit (Rounded to 4 decimal places)

2) Sanding = 60 / 6 = 10 Min / Unit

3) Drilling = 60 / 2.5 = 24 Min / Unit

4) Welding = 60 / 2 = 30 Min / Unit

5) Assembly = 60 / (0.8 + 0.8 +0.8) = 60 / 2.4 = 25 Min / Unit

(Note Total processing time at assembly = 25 * 3 = 75 Min / Unit)

Step 2: Determine the Bottleneck in the process:

The bottleneck is the workstation which takes the longest processing time per unit. Hence, the bottleneck for the given process is workstation "Welding".

Answer b) As calculated in step 1 of answer a, bottleneck time is 30 Minutes Per Unit. = 30.00 Minutes per Unit (Rounded to 2 decimal places)

Answer c) We will find the throughput time of the overall system by applying the following formula:

Throughput time of the overall system = Maximum of Processing Time (Sawing-Sanding-Welding-Assembly or Drilling-Welding-Assembly)

= Maximum [(8.5714 + 10 + 30 + 75) or (24 + 30 + 75)] (Values are taken from the step 1 of answer a)

= Maximum (123.5714 Minutes or 129 Minutes)

= 129 Minutes (Rounded to 2 decimal places)

Answer 2

A production process at Kenneth Day Manufacturing is shown in Figure S7.9 . The drilling operation occurs separately from, and simultaneously with, sawing and sanding, which are independent and sequential operations. A product needs to go through only one of the three assembly operations (the operations are in parallel).