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Enter your answer in the provided box. Calculate the volume of 11.7 M sulfuric acid that must be added to water to prepare 5.

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We will solve it by dilution equation M1V1= M2V2

M1= initial concentration = 11.7 M           V1= initial volume = ?

M2= final concentration = 0.808 M V2= final volume =5.879 L

V1 = M2V2/M1= 0.808*5.879/11.7 = 0.406 L

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