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Using the Python to do int operators +, -, *, //, and ** (not %), and...

Using the Python to do int operators +, -, *, //, and ** (not %), and the numbers 2, 3, 4, and 5, and an expression

that uses all four numbers exactly once, uses any three of the operators exactly once, and evaluates to 26.

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Answer #1

a=2

b=3

c=4

d=5

result=d**a-b+c

# first d**a is evaluated and it is having highest precedence 5**2=25 and +,- are having same prioirity

so its associativity is from left to right. Therefore 25-b=25-3=22+c=22+4=26

print(result)

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