Homework Answers
Q18.
Page size = 512 -> Page Offset = log 512 = 9 bits
So page number bits = 20( memory bits) - 9 = 11 bits
So total # of pages = 2^11 = 2048.
So the correct answer is 2048. Option (c)
Q19.
Page size = 512 bits -> Page offset = log 512 = 9 bits.
Page # bits = 16 - 9 = 7 bits.
A01F = 1010 0000 0001 1111
Page number = 101 0000=80
Page offset = 000011111 = 31
Option (c) is correct option.
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