Weight of the compound = 327 g
MW of the compound = 65.4 g/mole
Volume of the solution = 2500 mL = 2.5 liters
Molarity formula = moles of solute/volume in liters
No. of moles = weight/molecular weight = 327/65.4 = 5 moles
Therefore, Molarity = 5/2.5 = 2 mol/litre.
Units of molarity are moles/liter.
Nathan Nicholson Sabaté U DUall 2014 12. If a student dissolves 327g of a compound with...
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