Acetic acid has the formula CH_3COOH. The molar mass of Acetic acid is 60 0 grams...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
4. A solution is made by dissolving 15.00 grams of acetic acid and 3.25 grams of sodium acetate in 500.00 mL of water. What is the pH of the solution? The K, of acetic acid is 1.8 x 10. (Hints: First convert grams to mol and then determine the molarity of acetic acid and sodium acetate, ...) 5. What is the pH of a 2.50 molar solution of NHCl(aq)? The Ko for NH, is 1.8 x 105. 6. A certain...
Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass.
convert grams acetic acid to mole acetic acid then to mole isopentyl acetate then to grams isopentyl acetate and convert grams isopentyl alcohol to mole isopentyl alcohol then to mole isopentyl acetate then to grans isopentyl acetate. grams acetic acid mole ratio 1:1 for everything 130.18 isopentyl acetate mass 88.148 isopentyl alcohol mass
molarity of acid: 0.1435M volume:25ml 1. Use the molar mass and moles of acetic acid to determine the mass of the acetic acid in the 25.00-ml sample. 2. Calculate the mass/volume percentage (m/v %) by dividing the mass of acetic acid in grams by the volume of the vinegar sample in mL and multiplying by 100. 3. For the reaction of sodium hydroxide solution with a solution of hydrochloric acid: a. Write a balanced molecular equation for the reaction, including...
A student titrated 15.0 mL of acetic acid acid, HC2H302 ( Molar mass= 60 g/mol) solution with 25.0 mL of a 0.100 M NaOH solution The Molarity(mol/L) of HC2H302 required for complete titration is? HC2H302 + NaOH - NaC2H302 + H20 A) 0.0250 M B) 0.250 M C) 2.5M D) 0.0167M E) 0.167 mol
Benzoic acid has a molar mass of: 122.1 g/mole. What is the molarity of a benzoic acid solution in which 14.7 grams of solute are placed in 74.2 mL of solution. REPORT YOUR ANSWER TO 3 DIGITS DO NOT PUT UNITS IN THE ANSWER BOX Answer: -5 Benzoic acid is a weak acid with K = 6.46 x 10 What is the pH of a solution which has concentration: 0.580 M benzoic acid? REPORT YOUR ANSWER TO 3 DIGITS ACCURACY...
determination of the molar mass and ionization constatant of a weak, monoprotoc acid. ( Lab 8) I need help with the rest of the table. Instructor Name EXPERIMENTS DETERMINATION OF THE MOLAR MASS AND IONIZATION CONSTANT OF A WEAK, MONOPROTIC ACID Report Sheet B. TITRATION OF ACETIC ACID Trial 1 Trial 2 Trial 3 Acetic acid/L solution Volume of acetic acid (mL) Initial buret volume (ml) 3g/L 30 ml 30mL 30mL OmL OmL OML T 14mL 16ML | 15mL |...
Convert molarity to molarity convert the concentration of 0.500M son of acetic acid with a density of 1.0042 9/, l to malady mass of solution mass of solution mass of solvent mass of molality
8) What is the molarity (M) concentration of a solution when 18.37 grams of potasslum nitrite (KNO,) is dissolved in water to make 120 mL of solution ? GENERAL CHEMISTRY LABORATORY II 9) What will the final molarity concentration of the solution in question 8 if the volume is doubled? 10) How many milliliters of 0.153 M KMnO, solution are needed to react with 6.44 grams of iron(II) sulfate in aqueous solution? The balanced reaction is: 10 Feso, + 2...