Question

lengts are not important you can just give any number but dont forget dead load and live load values are moment form

a) B " Р A b) Section 1-1 Material: C25 $420 I 60 cm 30 cm For the structure given above; a) Draw the moment diagram b) For the element AB at midspan, The dead load moment: 4 tm The live load moment : 8 tm Calculate the neccessary reinforcement area As, Draw this reinforcement on the element AB. In case of insufficient beam height you can increase the beam height accordingly.

Answer 1

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As we can 18ox 100 = 0036x25x300 000 (550-0 4200) 6666666 = 550w -0.4210 0.42m) -550w +66666.6620 no = 135.16mm clearly see that, wlimano Hence section is under reinforced Henue for calculating Reinforcement Mu = 0.87 fy Ast Cd-0.42) Ast = 180x106 0.87% fyx (0-0.427) Asta 180 x 106 0.87 x 420x (550-0.42x135.46) Aste 180x106 180227.265 Ast = 998.73mm NON provide dia Hence ) 998.73 3.9294 2 عه 18mm for reibforcement baber of (n)= 1x 182 4 Hence are have to provide & boots lomon dia ay A Arrangement of bord, 65 mm Somm B B (4 bor, 18mm dia)

page 2 ?(sorry for the page arrangement during uploading)

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Ansive Morneant diagraon for the given frame B B tue We tie А レクサック D 60 cm 30 cm Ansiver - b Given Material mas to 420 fer = 25 MPa fy = 420 MPa D ourall depth = 60cm = 600 mm Breadth (B) = 30 cm z 300 mm Given Dead road moment z atm = 4x10 = 40 knim Live load moment = 8tm = 9x10 = 80 KN take clear cover somn. = 600-50=550mm, find no and nolim, for Fe 420 3) wrim = 0.46D = 0.484550 = 264 mm wlim. for solim, for of MU = 0.36 fok bw (d-0.421) 105(40 +80) *100 = 0·30x25x300% 4 (550 - 004200) effective depth calculation