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Probability calculation from z normal distribution table.
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According to recent surveys, 60% of households have personal computers. If a random sample of 185...
According to recent surveys, 60% of households have personal computers. If a random sample of 180...
According to recent surveys, 60% of households have personal computers. If a random sample of 180 households is selected, what is the probability that more than 60 but fewer than 100 have personal computers?
According to a recent survey 60% of households have personal computers. If a random sample of...
According to a recent survey 60% of households have personal computers. If a random sample of 180 households is selected, what is the probability that fewer than 100 have a personal computer. Approximate Binomial by Normal distribution
How many computers? In a simple random sample of 185 households, the sample mean number of...
How many computers? In a simple random sample of 185 households, the sample mean number of personal computer ls was 1.64. assume the population of the standard deviation is 0.47 a) construct a 99.9% confidence interval for the mean number of personal computers. round the answer to at least two decimal places. a 99.9% confidence interval for the mean number of personal computers is ---< mean <----- 2) In a sample of 75 clamps, the mean step to complete this...
in a simple random sample of 190 households, the sample mean number of personal computers was...
in a simple random sample of 190 households, the sample mean number of personal computers was 2.78. assume the population standard deviation is 0.41. a) a 99.8% confidence interval for the mean number of personal computers is ----< mean <----- 2) a simple random sample of eight college freshman were asked about how many hours of sleep they typically got per night. the results were 7.5, 8, 6.5, 24, 8.5, 6.5, 7, 7.5 a) the data contains an outlier that...
1. According to the U.S. Department of Commerce, 30% of Arkansas households had a computer in...
1. According to the U.S. Department of Commerce, 30% of Arkansas households had a computer in 2002. If 285 Arkansas households are selected at random, find the following probabilities: (Please show all necessary justifications.) a.The exact probability that 70 or fewer have a computer b. The probability that 70 or fewer have a computer using the normal approximation. c. The probability that 70 or fewer have a computer using the normal approximation with the continuity correction. 2. The probability that a...
How many computers? In a simple random sample of 150 households, the sample mean number of...
How many computers? In a simple random sample of 150 households, the sample mean number of personal computers was 2.91. Assume the population standard deviation is a =0.57. 5 alo Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places An 80% confidence interval for the mean number of personal computers is <<
According to the Consumer Electronics Manufacturers Association, 10% of all U.S. households have a fax machine...
According to the Consumer Electronics Manufacturers Association, 10% of all U.S. households have a fax machine and 52% have a personal computer. Suppose 91% of all U.S. households having a fax machine also have a personal computer. What is the probability that a randomly selected U.S. household has a fax machine and a personal computer? What is the probability that a randomly selected U.S. household has a fax machine or a personal computer? What is the probability that a randomly...
according to a government commission, 70% of all nations households have VCRs. In a random sample...
according to a government commission, 70% of all nations households
have VCRs. In a random sample of 15 households, what is the
probability that at least 13 have VCRs? Round to four decimal
places
According to a government co have VCRs? Round to four de O O 0 O 0.1268 0.7000 0.5000 0.8732
11. Pet Ownership A recent random survey of households found that 14 out of 50 householders...
11. Pet Ownership A recent random survey of households found that 14 out of 50 householders had a cat and 21 out of 60 householders had a dog. At a = 0.05, test the claim that fewer household owners have cats than household owners who have dogs as pets.
The national average SAT score (for verbal and math) is 1028. Suppose that nothing is known...
The national average SAT score (for verbal and math) is 1028. Suppose that nothing is known about the shape of the distribution and that the standard deviation is 100. Round the final answer to four decimal places and intermediate z-value calculations to two decimal places Source: New York Times Almanac. Part 1 out of 2 If a random sample of 245 scores was selected, find the probability that the sample mean is greater than 1041. Assume that the sample is...
How many computers? In a simple random sample of 150 households, the sample mean number of personal computers was 2.91. Assume the population standard deviation is a =0.57. 5 alo Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places An 80% confidence interval for the mean number of personal computers is <<
according to a government commission, 70% of all nations households
have VCRs. In a random sample of 15 households, what is the
probability that at least 13 have VCRs? Round to four decimal
places
According to a government co have VCRs? Round to four de O O 0 O 0.1268 0.7000 0.5000 0.8732
11. Pet Ownership A recent random survey of households found that 14 out of 50 householders had a cat and 21 out of 60 householders had a dog. At a = 0.05, test the claim that fewer household owners have cats than household owners who have dogs as pets.
The national average SAT score (for verbal and math) is 1028. Suppose that nothing is known about the shape of the distribution and that the standard deviation is 100. Round the final answer to four decimal places and intermediate z-value calculations to two decimal places Source: New York Times Almanac. Part 1 out of 2 If a random sample of 245 scores was selected, find the probability that the sample mean is greater than 1041. Assume that the sample is...
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