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According to recent surveys, 60% of households have personal computers. If a random sample of 185 households is selected, wha
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Answer #1

Probability calculation from z normal distribution table.

→ 6c. of Given that households have personal computers P=60% =0.6 Q=I-P = 1-0.6 - 0.4 Sample Size (m) = 185 PC 65 < X<la ) We

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