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1 points Seve angle of 48" with a magnetic field of 0.540 T. what is its...
An electron enters a uniform magnetic field B = 0.24 T at a 48 degree angle...
An electron enters a uniform magnetic field B = 0.24 T at a 48 degree angle to B. Determine the radius r and pitch p (distance between loops) of the electron's helical path assuming its speed is 3.5 times 10^6 m/s. See the figure Express your answer using two significant figures. Express your answer using two significant figures
7. A2 T uniform magnetic field makes an angle of 30 with the z-axls. Calculate the...
7. A2 T uniform magnetic field makes an angle of 30 with the z-axls. Calculate the magnetic flux through a 3 m? portion ofthexyplare.l®-jadA-BAco闭 (2.0 x 10つ(+ (3.0 ×們)J is moving 18. An electron that has an instantaneous velocity of s-(20 x10*)+(30 x10)'s moving through the uniform magnetic field (0.30)- (0.15T)J., Find the force on the electron due tothe magnetic field./-e@xあ 19. A capacitor in an LC oscilator has a maximum potential difference of 15 V and a maximum energy...
A 10cm×10cm square is bent at a 90∘ angle. A uniform 7.00×10−2 T magnetic field points...
A 10cm×10cm square is bent at a 90∘ angle. A uniform 7.00×10−2 T
magnetic field points downward at a 45∘ angle.(Figure 1)
What is the magnetic flux through the loop?
5 em 10 cm 45f 5 cm
1. A proton is moving at an angle of 80° to a uniform magnetic field. What...
1. A proton is moving at an angle of 80° to a uniform magnetic field. What is the relationship between the direction of the force on the proton and the direction of the magnetic field? * (1 Point) parallel to the magnetic field at an angle of 10° to the magnetic field at an angle of 80° to the magnetic field at an angle of 180° to the magnetic field perpendicular to the magnetic field 2. An electron is moving...
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle,...
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle, and its speed is 5.0x 10 m/s. (a) Describe the proton's motion in the magnetic field. (b) Calculate the radius of its path.
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle,...
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle, and its speed is 5.0x 103 m/s. (a) Describe the proton's motion in the magnetic field. (b) Calculate the radius of its path.
a) A proton moves at 500 m/s in a 2 T magnetic field. What is the...
a) A proton moves at 500 m/s in a 2 T magnetic field. What is the magnetic force experienced (magnitude and direction) if the angle between the velocity and field is: i) 0 degrees, ii) 90 degrees, iii) 45 degrees. b) An electron moving at 4.0x103 m/s in a 1.25 T magnetic field experiences a magnetic force of 1.40x10-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers.
A charged particle moves with velocity 1.5 km/s making angle 50° with the external magnetic field...
A charged particle moves with velocity 1.5 km/s making angle 50°
with the external magnetic field of magnitude of 0.6 T (see figure
below). The field exerts the 3.5 N force on the charge. The
direction of the force is out of the page/screen. What is the
magnitude and sign of the charge?
1. (15 points) A charged particle moves with velocity 1.5 km/s making angle 50° with the external magnetic field of magnitude of 0.6 T (sce figure below)....
A magnetic field whose magnitude is B = 1.66 T impinges on a circular magnetic dipole...
A magnetic field whose magnitude is B = 1.66 T impinges on a circular magnetic dipole of 100 turns, carrying a current of 3.33 A, whose radius is r = 2.66 cm. Because the magnetic dipole moment is rotated with respect to the field, the magnetic flux through the dipole is 03 = 2.64 x 10-3 Wb. (Wb is the abbreviation for 1 Weber = 1 Txm?). What is the magnitude of the electric potential energy of the magnetic dipole...
A magnetic field whose magnitude is B = 1.66 T impinges on a circular magnetic dipole...
A magnetic field whose magnitude is B = 1.66 T impinges on a circular magnetic dipole of 100 turns, carrying a current of 3.33 A, whose radius is r = 2.66 cm. Because the magnetic dipole moment is rotated with respect to the field, the magnetic flux through the dipole is OB = 2.64 x 10-3 Wb. (Wb is the abbreviation for 1 Weber = 1 Txm2). What is the magnitude of the electric potential energy of the magnetic dipole...
An electron enters a uniform magnetic field B = 0.24 T at a 48 degree angle to B. Determine the radius r and pitch p (distance between loops) of the electron's helical path assuming its speed is 3.5 times 10^6 m/s. See the figure Express your answer using two significant figures. Express your answer using two significant figures
7. A2 T uniform magnetic field makes an angle of 30 with the z-axls. Calculate the magnetic flux through a 3 m? portion ofthexyplare.l®-jadA-BAco闭 (2.0 x 10つ(+ (3.0 ×們)J is moving 18. An electron that has an instantaneous velocity of s-(20 x10*)+(30 x10)'s moving through the uniform magnetic field (0.30)- (0.15T)J., Find the force on the electron due tothe magnetic field./-e@xあ 19. A capacitor in an LC oscilator has a maximum potential difference of 15 V and a maximum energy...
A 10cm×10cm square is bent at a 90∘ angle. A uniform 7.00×10−2 T
magnetic field points downward at a 45∘ angle.(Figure 1)
What is the magnetic flux through the loop?
5 em 10 cm 45f 5 cm
1. A proton is moving at an angle of 80° to a uniform magnetic field. What is the relationship between the direction of the force on the proton and the direction of the magnetic field? * (1 Point) parallel to the magnetic field at an angle of 10° to the magnetic field at an angle of 80° to the magnetic field at an angle of 180° to the magnetic field perpendicular to the magnetic field 2. An electron is moving...
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle, and its speed is 5.0x 10 m/s. (a) Describe the proton's motion in the magnetic field. (b) Calculate the radius of its path.
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle, and its speed is 5.0x 103 m/s. (a) Describe the proton's motion in the magnetic field. (b) Calculate the radius of its path.
A charged particle moves with velocity 1.5 km/s making angle 50°
with the external magnetic field of magnitude of 0.6 T (see figure
below). The field exerts the 3.5 N force on the charge. The
direction of the force is out of the page/screen. What is the
magnitude and sign of the charge?
1. (15 points) A charged particle moves with velocity 1.5 km/s making angle 50° with the external magnetic field of magnitude of 0.6 T (sce figure below)....
A magnetic field whose magnitude is B = 1.66 T impinges on a circular magnetic dipole of 100 turns, carrying a current of 3.33 A, whose radius is r = 2.66 cm. Because the magnetic dipole moment is rotated with respect to the field, the magnetic flux through the dipole is 03 = 2.64 x 10-3 Wb. (Wb is the abbreviation for 1 Weber = 1 Txm?). What is the magnitude of the electric potential energy of the magnetic dipole...
A magnetic field whose magnitude is B = 1.66 T impinges on a circular magnetic dipole of 100 turns, carrying a current of 3.33 A, whose radius is r = 2.66 cm. Because the magnetic dipole moment is rotated with respect to the field, the magnetic flux through the dipole is OB = 2.64 x 10-3 Wb. (Wb is the abbreviation for 1 Weber = 1 Txm2). What is the magnitude of the electric potential energy of the magnetic dipole...
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