Question

A marble of inertia m is held against the side of a hemispherical bowl as shown in (Figure 1) and then released. It rolls without slipping. The initial position of the marble is such that an imaginary line drawn from it to the center of curvature of the bowl makes an angle of 30? with the vertical. The marble radius is Rm = 10 mm, and the radius of the bowl is Rb = 140 mm .

center of curvature 300

Part A

Determine the rotational speed of the marble about its center of mass when it reaches the bottom.

?f =   s?1
0 0
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Answer #1

Moment of inertia of the bar is I =-mr Angular velocity According to conservation of energy - COS Hence velocity 10gf, (1 -co

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