0. (10 Points) A four-core i7 has a 8 MB L3 cache 8-way set associative of...
Q2. Consider a four-way set associative cache with a data size of 64 KB. The CPU generates a 32-bit byte addressable memory address. Each memory word contains 4 bytes. The block size is 16 bytes. Show the logical partitioning of the memory address into byte offset, cache index, and tag components.
A 256kiB (2^18 bytes) cache has a block size of 32 bytes and is 32-way set-associative. How many bits of a 32-bit address will be in the Tag, Index, and Bock Offset?
question 2 and 3 2. Determine how many sets of cache blocks will be there for the following Cache memory size (in bytes) Direct Mapped Blocks Size (in bits) 32 64 218 2-way Set Associative Block Size (in bits) 32 64 A 2A6 [0.5 * 16 = 8] 4-way Set Associative Block Size (in bits) 32 64 SK 64K 256K 3. The physical memory address generated by a CPU is converted into cache memory addressing scheme using the following mapping...
2. Set Associative Cache (36 pts) Given the following address access stream, please answer 2.1, 2.2 and 2.3. All the addresses are 32-bit. The sequence is shown below. Load Load Store Store Load 0x22160788 Ox09000E40 0x1265024C 0x22160484 0x1265014C 2.1 (11 pts) A 512 bytes, 2-way writeback cache. The cache line size is 64 bytes. Please calculate the number of bits used for tag, set index, and offset. Number of tag bits = Number of index bits = Number of offset...
please solve e & f for this question. 1. (40 points) The Corei7-6700K microprocessor has 3 cache levels about the L2 cache per core and the main memory: (more detailed information can be found at: http://www.cpu-world.com/CPUs/Core i7/Intel-Core%2017-6700.html The following is the information Memory is byte addressable Maximum memory capacity is 64 GB (G=230). Cache capacity is 256 KB (K=210) 4-way set associative is used - Block offset size is 6 bits. If CPU has generated the physical address (411234)10, what...
Make an assumption that your cache is either: Fully associative Direct mapped Two-way set-associative Four-way set-associative determine: the size of the Tag and Word for Associative cache; OR the size of the Tag, Line, and Word for Direct-Mapped Cache ; Or the size of Tag, Set, and Word for K-Way Set-Associative Cache. You may make any assumptions necessary including the number of Words in each block (recommend 2 or 4 or 8)
Consider a 32-bit microprocessor that has on-chip 16Kbyte four-way set associative cache. Assume that cache has a line size of four 32-bit words. How many number of set are there? Sketch block diagram of this cache showing its organization. Where in the cache is the word from memory location ABCDE7F4.
) Consider an 8-way associative 64 Kilo Byte cache with 32 byte cache lines. Assume memory addresses are 32 bits long. a). Show how a 32-bit address is used to access the cache (show how many bits for Tag, Index and Byte offset). b). Calculate the total number of bits needed for this cache including tag bits, valid bits and data c). Translate the following addresses (in hex) to cache set number, byte number and tag (i) B2FE3053hex (ii) FFFFA04Ehex...
Consider a 2-way set associative cache consisting of 8 blocks total of byte-addressable memory with 4 bytes per block. Assume that the cache is initially empty. Given the following address sequence, fill in the table below. Time Access Tag Set Offset 3 10010001 11001001 10110110 10101011 10110010
Assume a 16-way set associative cache that holds 4096 bytes, where each block is 16 bytes. Assuming an address is 32 bits and that cache is initially empty complete the table below. (You should use hexadecimal numbers for all answers.) Address TAG Cache location (block) | Offset within block OxOFFOFABA 0x00000011 0xOFFFFFFE 0x23456719 OxCAFEBABE Which, if any of the addresses will cause a collision (forcing the block that was just brought in to be overwritten) if they are accessed one...