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Albino rabbits (lacking pigment) are homozygous for the recessive c allele (C allows pigment formation). Rabbits...

Albino rabbits (lacking pigment) are homozygous for the recessive c allele (C allows pigment formation). Rabbits homozygous for the recessive b allele make brown pigment, while those with at least one copy of B make black pigment. True-breeding black rabbits were crossed to albinos. F1 rabbits, which were all black, were crossed to the double recessive (bb cc). The progeny obtained were 40 black, 60 brown, and 100 albino.

What phenotypic proportions would have been expected if the b and c loci were unlinked?

How far apart are the two loci?

What are the genotypes of the parents?

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Answer #1

Answer:

BBCC (true-black) x bbcc(albino)----P1

BbCc (black)-----------------------------F1

BbCc (F1) x bbcc (double recessive)

bc

BC

BbCc (black)

Bc

Bbcc (albino)

bC

bbCc (brown)

bc

bbcc (albino)

If the genes are unlinked, the phenotypic proportions of the cats are as follows.

Black = ¼ = ¼ * 200 = 50

Brown = ¼ = ¼ * 200 = 50

Albino = ½ = ½ * 200 = 100

Recombination frequency = (Recombinants / Total progeny)100

RF= (60/ 200)100

= 30%

RF(%) = Distance between the genes (m.u.)

So the distance between the genes = 30 m.u.

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