) How would you prepare 400.0 mL of a 0.500M HCl solution from a stock bottle...

Question

Question

Answer 1

Answer #1

Number of moles of HCl = molarity * volume of solution in L

Number of moles of HCl = 0.500 * 0.4 = 0.2 mole

Molarity = number of moles of HCl / volume of solution in L

12.0 = 0.2 mole / volume of solution in L

volume of solution in L = 0.2 / 12.0 = 0.0167 L

1L = 1000 mL

0.0167 L = 16.7 mL

Therefore, the volume of solution = 16.7 mL

Therefore, by taking 16.7 mL of 12.0 M HCL we can prepare 400.0 mL of 0.500 M HCl solution

Answer 2

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