Answer) 1.57 M is the molarity of benzoic acid solution.
Explanation:
Calculate the number of moles of benzoic acid as follows:
Number of moles = mass/molar mass
Number of moles = 17.1 g/(122.1 g/mol) = 0.14 mol
1 mL = 0.001 L
Volume of solution = 89.2 mL×(0.001 L/1 mL)=0.0892 L
Molarity = number of moles of solute/volume of solution in litre
Molarity =0.14 mol/0.0892 L =1.57 M
Benzoic acid has a molar mass of: 122.1 g/mole. What is the molarity of a benzoic...
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