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One copy of the human genome is 3 billion (3 X 109base pairs). Pretend that instead...

One copy of the human genome is 3 billion (3 X 109base pairs). Pretend that instead of 4 bases (AGCT) there are 5, and that the 5th base (called D) pairs with itself. Pretend also that all 5 bases are present at equal frequency in the human genome.

Suppose you digested to completion one copy of the human genome with the enzyme Eco RI (recognition sequence 5'-GAATTC).

A Given the information above about the 5thbase, what would be the average size of the DNA fragments?And how many fragments are produced?

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Number of fragments in human genome = 192000

Calculation is given blow ___

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