Question

QUESTION 13 [CLO-5] At 1000 K, the equilibrium constant for the reaction 2NO (g) + Br2 (g) ==== 2NOBr (g) is Kp = 0.013. Calculate Kp for the reverse reaction, 2NOBr (g) 2NO (g) + Br2 (9) ==== -0.013 1.1 77 0.013 0 1.6x 10-4

Answer 1

Question 13

For the reaction 2NO(g) + Br₂(g ) == 2NOBr(g)

Equilibrium constant , Kp = [P_NOBr(g) ]² / [P_NO(g)]²[P_{Br2(g )}] = 0.013

So for the reverse reaction 2NOBr(g) ==  2NO(g) + Br₂(g ) Equilibrium constant , Kp = [P_NO(g)]²[P_{Br2(g )}] / [P_NOBr(g) ]² , the equilibrium constant for the forward rectrion is inverse of the equilibrium constant fro the backwsrd reaction.

Therefore, Kp^' = 1/ Kp   = 1 / 0.013       Kp^' = 76.92 ~ 77(approx)