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(Ans) Given the curve C: x=t , y=t^2 and z=t^3.
Now to determine the points where the given curve intersects the cylinder y= 16 - x^2--->(1).
By substituting the x and y values inin the cylinder equation, we get
t^2 = 16 - t^2.
2t^2 = 16.
t= +2√2 and -2√2.
Now the values of x,y and z for the above values of t are given below.
For t=2√2 then x=2√2 , y=8 and z= 16√2.
For t=-2√2 then x=-2√2, y=8 and z= -16√2.
Therefore the points of the given curve to intersect the cylinder are given below.
(x,y,z) points are ::
(2√2, 8 , 16√2) and (-2√2, 8 , -16√2).
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