Question

3. 15 MF Find the equivalent capacitance of the circuit shown in the diagram. If an 18 V battery is connected to terminals A and B, find the charge on each capacitor, the voltage across the 8.2 pF and 22 F capacitors, and the total energy stored in the circuit A B 8.2uF 22uF

Answer 1

sol. A b (3= 15 ur TH (a) Capacitances 'c' and C2 are in series combination o So their equivalent capacitance t th given by? 22 ufa C2 4 + & cep is 8.2 uf ei + + ㅗ a 802 22 Cep (. + ㅗ 22 4 soar up 8.2 mi Non this ee is ₂ = 15 MA So the equivalent circuit : P an alled with capacitan q

18V Ce= (cep +G) list 5.60) 20.97 per Cepe do. 97 per (6) Potential difference ov= This potential difference is same combination (s. 2 MA change 15 ufa q q'= (15 x 18 18) нс is per an d aud 22 of 22 f) so i CV 93 220 fic (8.2 pef and 22 ma). 107.46 uc change combination of 9. (5.97 418 this charge en series. 8.2 pf is oud 8.2 appeared on both 22 pf because ME they que 입 VE vollage across 107.46 v 8. Ź Vollage across } 13.lor 4" 107.46 across 22 ur V" Via 4.88. V

cage No. vollage acwss 8.2 pet = 13. lov across 22 MA 1.88 v vollage = co Total ener gy stored LS given by : U= I Cep V2 T X 2o. Hos 97 X x (18) 339.7. 14 J a 33 97.14 J U LI

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