Question

LAB 8: GEOMETRICAL OPTIUS: RAY TRACING PART I REFRACTION PLANE NORMAL FOR THE OPPOSITE > REFRACTED RAY INSTRUCTIONS * PRINT this sheet * Using a protractor, measure the angle of incidence is the angle of refraction or for the incident plane * Find the index of refraction of the block n= sin i Sin * Repeat for the opposite face > NORMAL FOR THE INCIDENT PLANE INCIDENT RAY LIGHT SOURCE Pg 5 of 8.

I am having trouble with answering part 2 of these ray tracing, can you please help me?

Answer 1

Solution of Refraction:

INSTRUCTION this s * Using a po * PRINT NORMAL FOR THE OPPOSITE PLANE the angle REFRACTED RAY angle of incident F * Find the of the block na s * Repeat 34° NORMAL FOR THE INCIDENT PUTE INCIDENT RAY

NORMAL FOR THE OPPOSITE PLANE REFRACTED RAY INSTRUCTIC PRINT this * Using a p the angle angle of incident * Find the of the blow na * Repeat 21 NORMAL FOR THE INCIDENT PUNE INCIDENT RAY

As shown in figure, the incident angle is $i=34\degree$ and refracted angle
T= 21
. The index of refraction of the block is calculated as:

$n=\frac{sin \ i}{sin\ r}$

$\therefore n=\frac{sin \ 34\degree}{sin\ 21\degree}$

..n= 1.56

INSTRUCTION PRINT this * Using a pri NORMAL FOR THE OPPOSITE PLANE the angle REFRACTED RAY angle of incident * Find the of the block na s s * Repeat 20 NORMAL FOR THE INCIDENT PLANE INCIDENT RAY

PLANE NORMAL FOR THE OPPOSITE the angle REFRACTED RAY INSTRUCTIO * PRINT this * Using a po angle of incident * Find the of the bloc n 34 * Repeat > NORMAL FOR THE INCIDENT PLANE INDON RAY

Similarly, for the opposite face, as shown in figure, the incident angle is $i=20\degree$ and refracted angle $r=34\degree$ . The index of refraction of the block is calculated as:

$n=\frac{sin \ r}{sin\ i}$

$\therefore n=\frac{sin\ 34\degree}{sin \ 20\degree}$

${\color{Blue} \therefore n=1.63}$

Solution of Convex lens:

LA 68: SOMETRICAL OPTICS PAR CONVEX LE TRUCTIONS xrint this shee sing a swer, The focal length Repeat for con LENSE on pg 9.7 cm

As shown in the figure, since the rays are paraxial, the image is formed at the focal point and therefore, the focal length of convex lens is

Solution of Concave lens:

LAB GEOMETRICAL PART I: CONCAT 7.2 cm

As shown in the figure, since the rays are paraxial, the image is formed at the focal point and therefore, the focal length of concave lens is