Question

U Question 13 O pts 1) The bulk modulus of water is 2.2 x 10° Pa 22 x 10 N/m?). By how much does a cubic meter (10mof water decrease in volume when it is taken from the surface of the ocean down to a depth of 1.0 km, where the pressure is 98 10Pa greater than at the surface? II) A 0.250 kg object attached to a spring oscillates on a frictionless horizontal table with a frequency of 4.00 Hz and an amplitude of 20.0 cm. Calculate a) the maximum elastic potential energy (PE) of the system, and b) the displacement of the object when the PE is one-half of the maximum Upload Choose a File

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Answer 1

ين 3. Solution 7 13 → bulk modulus (k) = 2.2X109 Pascal initial volume w l.om Pressure at surface (li) 1.01 X10 Pressure at depth of welter (P) = 9.8*10* + Pi 5 lo Pt-Pi 9.8x106th - AP AP = 9.88106 Pascal we know bulk modulus ů given by 지 у др. AV 202X102 1 m² x 9 obx106 AV 9.88106 2.28109 AV AV = 4.5454 X10 4.5454 x 10-3 m3 Aus. üleau mall of the object (m) = 0.25kg frequency (1) = 4H3 and 274 8a rad (s. und Amplitude (A) = maximum potential energy [CP.E.) mor] į mw?A? 0.2 m (P. E.) mar 1 / 1 x0.25% (8XjPx (0.232 Pito) max. = 3.155 Joule. Ans. Se (b) tfoto Jat some displacement IP. E.) maxe 2 2 = ) mw2x2 mara 2 wa mw?A2 1 A² » 2 5- £x? x2 A² 2 2 4 X A 0.2 -0. 141 m Aus. IN z

810m Solution - 14'_319) length of the string (I) = tension in the string (T) = 49 N mass of the string (m) = 409_ 0.04 kg A А N fixed end > fixed end A 712 가 A 5014 진 374 speed of the une in the string ů given by where Ty tension T प and Tol [uam] 5 i 49x8 9800 9.89 X10 0404 98.9 mil since, there are three loops in the etring ito 361 8: 3 2 A l= 16 3 position of Antinodes are 11A, 3114 and 5x4 as shown in the above diagram and A = 16/a.m Ans. (b) nu frequency (W) 3* 98.9 22 2x8 = 18.544. H.3 Aus.