1. Propose a mechanism:
Starting material: butyraldehyde
Solvent: water
Reagent: Potassium Hydroxide(KOH)
Final product: 2-ethyl-3-hydroxy-hexanal
2. Propose a mechanism:
Starting material: Methyl Propionate
Solvent: water
Reagent: HCl
Final product: propionic acid
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1. Propose a mechanism: Starting material: butyraldehyde Solvent: water Reagent: Potassium Hydroxide(KOH) Final product: 2-ethyl-3-hydroxy-hexanal 2....
starting material is butyraldehyde ,the solvent is ether and the reagent is Naoh For this assignment, the target compound that you should synthesize is 2-ethyl-hex-2- enal.Choose the correct starting materials from chalkboard. Write the chemical equation and depict the mechanism and give the structure of all intermediates.
3. Write a detailed mechanism to yield 3-methyl-2-oxacyclopentanone. What is the hydroxy acid (starting material) for this lactone formation? Hydroxy acid
I am trying to figure out the starting materials, solvent, and reagent to form the product methyl-2-methyl-3-oxobutanoate. I can choose from the following starting materials: Methyl acetate, Methyl propionate, and 1,7-Dimethyl-heptanedioate. I can choose EtOH or Et2O as a solvent. I can choose the reagents listed in the picture provided. Which would be best to make the desired product and what would the mechanism be? H, SO Ha MCPBAANCE BH BryNaBH, PCC OSO KOHLDA HNO, Sod, NaOH, G0; H₂O 11
the solvent is ether, reagent is KOH and the starting material is benzaldehyde and 2,2-dimathyl-pentan-3-one would you help me with mechanism, i am confuse with the mechanism For this assignment, the target compound that you should synthesize is 2,4,4-trimethyl-1- phenylpent-1-en-3-one. Draw the structure of the target compound and retro-synthesize it. Write the chemical equation and depict the mechanism and give the structure of all intermediates.
what is the mechanism for 2-ethyl-3-hydroxy-hexanol? please show electron arrows. The starting materials are acetaldehyde, butanol, EtOH, KOH Thank you
Choose a starting material and a reagent (A-F) to synthesize the given product. When [Select] is treated with Select ] it will produce 3-methyl-2-butanol REAGENTS CoH5MgBr (in ether) C2H5OH (excess) Jones' reagent, CrO3 in H30(+) followed by H30(+) workup acid-catalyst, heat (-H2O) NaBH4 in CH3OH (CH2)5NH (piperidine) acid-catalyst, heat (-H20) N2H4 KOH & strong heat
What is the IUPAC name of the given molecule? OH Br 1-bromo-2-ethyl-2-hydroxy-3-methylpentanoic acid 2-ethyl-3-methylpentan-2-ol-1-carboxyl bromide 2-ethyl-3-methyl-2-ol-pentanoyl bromide O2-ethyl-2-hydroxy-3-methylpentanoyl bromide What statement is TRUE about the mechanism for the reaction shown here? CH,(CH)2CO,CH, NaOH CH3(CH12COCH excess heat CH3(CH)2CO,CH2 Water attacks the carbonyl carbon to form a tetrahedral intermediate. The first step of the reaction involves protonation of the ester carbonyl oxygen. One of the products formed is glycerol. The hydroxide deprotonates the alpha carbon. Which bases among the following is/are used...
Create a synthesis with butyraldehyde as the starting material and 3-bromo-2-methylheptane as the target product. Thank you :)
choose a starting material (4-methyl-2-pentanone, 2-methyl-3-pentanone, 2,3-dimethylbutanal) and a reagent from A-F to synthesize 2,2-dimethoxy-4-methylpentane. Choose a starting material and a reagent (A-F) to synthesize the given product. When [Select ] is treated with (Select ] it will produce 2,2-dimethoxy-4- methylpentane. REAGENTS C. A. Jones' reagent, Croz in CH3MgBr (in CH3OH ether) (excess) followed by acid-catalyst, H30(+) workup heat (-H20) H₂O(+) NaBH4 in CH3OH (CH2)5NH (piperidine) N2H4 KOH & acid-catalyst, strong heat heat (-H20)
What would you expect to see comparing the solubility of 2-hydroxy-3-methoxybenzaldehyde (starting material) and 2-hydroxy-3-methoxybenzoic acid (product) in acidic and basic media (See solubility test 4.1.1)