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Suppose a chemist starts with an aqueous buffer that contains 0.05 mol of HCN and 0.07...
An aqueous solution contains 0.034 M Brand 0.079 MT. A chemist wishes to do a fractional precipitation experiment in which he slowly adds Pb+2, which can form ppts of PbBr2 (s) [Ksp = 4.6 x 106 and Pbl2(S) [Ksp= 8.4 x 10 °). Which of the following is entirely correct? a. I precipitates first when [Pb2+1 = 3.4 x 10-7M b. Br precipitates first when [Pb2+] = 1.4 x 10-4M c. I'precipitates first when [Pb2+] = 1.1 x 10-7M d....
An aqueous solution contains 0.3 M Cl'and 0.4 MF: A chemist wishes to do a fractional precipitation experiment in which he slowly adds Pb2+, which can form ppts of PbCl2(s) [K sp = 1.6 x 10-6] and PbF, (s) [Ksp = 7.1 x 10-7]. Which of the following is entirely correct? Pb2+ 0.3 M cl- 0.4M F- Cl precipitates first when [Pb2+] = 1.8 x 10-4 M. OF precipitates first when [Pb2+] = 1.0 x 10-4M. Cl precipitates first when...
7) At 1500°C the equilibrium constant for the reaction CO(g) + 2H2(g) → 키.4x10-7. Calculate AG)for this reaction at 1500°C A) 105 kJ/mol B)-105 kJmol C)1.07 kJ/molD) CH,011(g) has the value K, D)255 8) Determine the equilibriurn constant K, at 25°C for the reaction Nag) + 3H2(g) → 2NHO 3 kJ/mol A) 1.52 x 106 B) 6.60 x 10 9) Predict the sign of AS for the reaction 02(g) → 20(g). C) 828 x 10D) 2.60 A) Negative B) zero...
In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of a Zn/Zn2+ half-cell and an H2/H+ half-cell under the following conditions: [Zn2+ ] = 0.021 M [H+ ]= 1.3 M partial pressure of H2 = 0.32 atm. Calculate Ecell at 298 K (enter to 3 decimal places). Zn2+ (aq) + 2e − ⟶ Zn(s) E° = − 0.76 V 2H+ (aq) + 2e − ⟶ H2(g) E° = 0.00 V We were unable...
In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of a Zn/Zn2 half- cell and an H2/H half-cell under the following conditions: [Zn2] = 0.042 M [H]- 19 M partial pressure of H2 =0.37 atm. Calculate Ecell at 298 K (enter to 3 decimal places). Zn2 (aq) + 2e +2H (aq) + 2e1 Eo-0.76 V E 0.00 V Zn(s) H2(g)
Pb2+(aq) + 2e− ⇌ Pb(s) E° = -0.126 V 2H+(aq) + 2e− ⇌ H2(g) E° = 0.000 V E°cell (in V)= 0.126 V 2. The electrochemical cell is comprised of a Pb electrode in a 1.67 × 100 M solution of Pb2+ (aq) coupled to a Pt electrode in a solution containing H+ (aq) where the pH of the solution is 0.37 and the partial pressure of H2(g) is 0.571 atm. The temperature of the cell is held constant at...
a) 4.9 x 10'M b)24x10 M c)5.8x 1010 M )1.2 x 10 M 19. Which one of the following compounds will have the lowest molar solubility in pur water? b) CuS, Ksp 1.27x103 d) ZnS, Ksp = 1.6 x 10-24 a) PbS, Ksp 9.04 x 102 e) Al(OH)s, Ksp 3 x 1034 What is the molar solubility, i.e. [Fe , in a saturated aqueous solution of 20. Fe(OH)20) Fe(OH(s)Fe2+(aa) + 201H (ag), Ksp 4.87 x 101" a) 2.44 x 1017...
Ag3+(aq) + e− ⇌ Ag2+(aq)E° = 1.800 V2H+(aq) + 2e− ⇌ H2(g)E° = 0.000 V1. Answer the following questions under standard conditions(a) The half-cell containing Ag2+/Ag3+ is the cathode .(b) The half-cell containing H+/H2 is the anode .(c) What is E°cell (in V)? Report your answer to three decimal places in standard notation (i.e., 0.123 V).1.800 V(b) What is ΔG° (in kJ/mol) for the process that is occurring in the electrochemical cell? Report your answer to three significant figures in...
help with these please Use the References to access important values if needed for this question. What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cu2 concentration is 9.24x104 M and the Cr3 concentration is 1.47 M ? 3Cu2 (aq)+2Cr(s)3Cu(s) + 2Cr (aq) V Answer: The cell reaction as written above is spontaneous for the concentrations given: What is the binding energy in kJ/mol nucleons for silver-107? kJ/mol...
Use the tabulated half-cell potentials to calculate ΔG° for the following balanced redox reaction. (F = 96,485 C/mol e) 2Li( s) + Cl 2 ( g) → 2 Cl - ( aq) + 2Li +( aq) Eº Li+(aq) + e- → Li(s) -3.04V Cl2 (g) + 2e- → 2 Cl- (aq) +1.36 V a. -425 kJ b. -849 kJ c. -8.49 x 10 5 kJ d. +324 kJ