Ans) The correct answer is "C" i.e allolactose
(Allolactose acts as an inducer of the lac operon. It binds to the repressor and reduces its affinity to bind to the operator region. Since the lac repressor cannot bind to the operator, the RNA polymerase can now easily access and bind to the promoter region to start the transcription of Lac z,y,a genes to turn ON the lac operon.
cAMP-CAP complex and lactose both are required for the lac operon to be turned ON but cAMP-CAP complex do not act as an inducer.
When both lactose and glucose is added into the medium, the lac operon is turned OFF because glucose will inhibit the synthesis of enzymes required for the lactose metabolism.This is known as glucose effect.When the glucose is depleted from the medium, synthesis of lactose metabolism enzymes starts and the lac operon will be turned ON.
Ans) The correct answer is "A" i.e mRNA
(Codon refers to the nucleotide triplet present in mRNA which is read or decoded by the ribosome by bringing appropriate tRNA having anticodons which are complementarily to the codons in the A and P site of the ribosome).
The inducer of the lactose operon in E. coli is CAP. cAMP. allolactose. glucose. galactos Codons...
Question 12 2 pts What is the role of CAMP in regulation of the lactose operon? CAMP is a repressor of the lactose operon and turns off gene expression of the lactose operon CAMP is an activator and prevents the repressor protein from binding to the operator region of the operon which allows for the lactose operon to be turned "on". 5 CAMP is an inducer of the lactose operon and also an activator since it prevents the repressor protein...
The natural inducer for the lac operon is A) lactose B) allolactose C) ?-galactosidase D galactose E good grde hydrolase
In E coli the lac operon will express enzymes for the digestion of (Glucose/Lactose) when it is present, but if both the sugar mentioned before and (Glucose/ Lactose) are present the lac operon is repressed, resulting in the (Glucose/ Lactose) being used first. If there are high levels of cAMP, this means (Glucose/Lactose) levels are low, this results in a (Represser/Promoter) being activated and (Decreasing/Increasing) transcription of the lac operon.
In the lactose operon of E. coli, the CRP-cAMP complex is a(n) _____ of transcription. A. positive regulator B. enhancer C. silencer D. negative regulator
Quiz 10 1. (2 points) Which of the following conditions would lead to the highest levels of lac operon expression? a) High lactose, high glucose b) High lactose, low glucose c) Low lactose, high glucose d) Low lactose, low glucose e) None of the above would have any lac operon expression 2. (2 points) Which of the following is true concerning molecular genetics? a) tRNA carries amino acids into the nucleus in eukaryotic cells b) DNA polymerase moves towards the...
You plate colonies of E. coli with the lac operon genotype of I+P+OCZ+CAP+ on 1) a medium containing only glucose, and 2) a medium containing only lactose. You isolate mRNA from bacteria from each medium and do a Northern blot with a probe for β-galactosidase. Draw the results.
The gene machine program shows you what happens when lactose is present in E. coli, and how the lac operon is under negative control. However, the lac operon is also under positive control from a protein called CRP, eAMP Receptor Protein. The absence of the lac repressor is essential but not sufficient for effective transcription of the lac operon. RNA polymerase also depends on the presence of CRP. Like the lac repressor, which can bind to the DNA and lactose....
26. The lac operon in E. coli consists of genes that code for enzymes necessary for the breakdown of lactose. When lactose is absent, the operon is inactive because a repressor protein binds to a specific site in the lac operon. When lactose is present, lactose molecules bind to the repressor protein, causing the repressor protein to dissociate from the binding site. In the absence of glucose (a preferred energy source for bacteria), the protein CAP binds to a regulatory...
Answer please
E. coli expresses a specific gene in the presence of lactose. The expression of this gene is under control by the lac operon, a sequence of nucleotides in the DNA which control the lac Operon al DNA ) laci CAP) (o) laczlacY
To study the lac operon in E. coli, you added IPTG in the growth media, which is another analog of allolactose that is an inducer of the lac operon but is not metabolized by β-gal. You measured the activity of the enzyme β- galactosidase (β-gal) by X-gal. After mutagenesis (induce mutations) you find mutants that never turn blue, which DNA component(s) could produce such phenotype?