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A true breeding plant for round and yellow seeds is crossed to a true breeding wrinkled and green seeds. All progeny are roun

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Answer #1

Here, the correct option is d) 32 map units.

Explanation -

Let ' R ' be the dominant allele responsible for the round seeds and let ' r ' be the corresponding recessive allele responsible for the wrinkled seeds.
Also, let ' Y ' be the dominant allele responsible for the yellow seed and let ' y ' be the corresponding recessive allele responsible for the green seed.
Let us suppose that gene for the seed shape (round and wrinkled ) and the gene for the seed colour (yellow and green) are linked
Now, the genotype of the parents = RY/RY and ry/ry
Their cross to produce F1 offsprings -

Parents: RY/RY X | Gametes: ry I ry V Ty (RY fi offsprings: RY lry (Round and yellow seed Now the Fi offering ore crossed toParents RY/oy x ry/oy J Comets: (RY) (my ry (Ry) Round 2 affopping: RY Ro rY ry ry Ryleg {rylay Rylsy /oY/ry I consenkled |

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