Question

Problem 9.72 Review The thin-walled pipe has an inner diameter of 0.5 in and a thickness of 0.025 in Part A Figure 1 of 1 It is subjected to an internal pressure of 416 psi and the ancial tension and forsional loadings shown, determine the principal stress at a point on the surface of the pipe. (Figure 1) Enter your answers numerically separated by a comma. | ΑΣΦινος ? 010 31.398, 20,308 ksi 200 lb 200 Submit Previous Answers Request Answer X Incorrect; Try Again: one attempt remaining

Answer 1

4.16 KSI soin's 6.930 23.176 Section Properties! A = T(0.2752-0.252) 0.013125 T in2 23.176 R-2.28 I I CO.2754 -0.254) 2 2.84 768 X10-3 in y 5545 Normal strens due to this wall ) since the t 0.25 0.025 = 10 ; Thin cylinder analys's ü valid Icongitudinal = ☆ the 200 + 41600.25) 260.025 ) 0.013125 TT 6930.436 Psi hoop = 416 +0.25 pre t 4160 psi 0.025 Applying torsion formula to calculate shean stress! 1 Tc 20X12 X 0.275 = 23176.761 2.84768 *10-3 using mohra's circle In accordance with the sign convention; 0x = 6930.4136 psi, og = 4160 psi , CS Scanned with CamScanner Zxy = = 23176.761 psi

6930.436 + 4160 Tango ox+by 2 2 = 5545.218 PSE The Co-ordinates for reference points A and a are! A(6930.436,- 23176-761) c(5545-28,0) The readies n : circle of RA V (6930:436-5545-218)+23176.381)2 R = 232 18.119 psi' The co-ordinates of point B and D represents o and Da. oi 5545:218 + 232 18.119 o = 28763. 337 psi 28.763 Ksi yan - 23218.119 Tas 5545-218 --17672.901 psi → Ans. Das -17.672 ksi (Thank you) CS Scanned with CamScanner