Question

Refer to the following circuit, assuming IS = 1.0 pA; D1 is a generic rectifier diode, and it is at temperature of 50⁰ C. Calculate the voltage drop VR across R1 for

(a) R1 = 1.0 Ω,

(b) R1 = 10 Ω,
(c) R1 = 100 Ω,

(d) R1 = 1.0 kΩ.

R1 1.0Ω D1 V1 -1.ον

Answer 1

Given circuit can be drawn as Below Pg Ri=12 -v-lv VD Current through diode. can be as ID = Is Le hive J-o Where It = 11.600 it- teasperatione in keloins = 273+50 11, 600 = 37.844. mv a When Ri= 12 ID = (v1 - VD)/RI - Vo Vox 103 e TX87.844 e TX27.844 1 equation ① ID= 1x10-12/1 eet. from 0 2 1-1= 10:02, vo via solving above equalion using calculator we get -) Now voltage choop Vei= V-vo on = 1-0.7326 0.2674 volts b When Ri= 102 Io = [vi- vo] 3. - Vo 10 Ri from eq and

Vox 103 1X2 7.844 1-VD 10 -12 = I x 10 Solving above equation using calculator we we get = Now voltage doop VRI- VVD -0.674 = 1-0.674 - 0-326 Volts c When Ri=loor then ID= VI-VD 1-VD Ri 4 100 bom equation o el Vox 103 12 1-VD 100 -10 1x27.844 e get Solving above equalion using calculator = Now Voltage doop VRI= VR - VD VRI= 0.3854 volts d When Ri= 1 kr 1-0.6146 ID = V1-VD I-VD 1000 4 R1 Som equalcon Ol I-VD 12 10 VDXUS 1x 27.844 1 Solving above equation wit wsing calculator we get =) How Voltage doop VRI= VI-VD VD=0.55452 = 1 0.55 452 VRI= 0.44 548 Volts.
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