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A random sample of n=7 observations are drawn from a normal population with mean and variance...

A random sample of n=7 observations are drawn from a normal population with mean and variance σ^2. The mean and variance of the sample are 1.45 and 2.07 respectively. Calculate a 90% confidence interval for the population standard deviation.

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Answer #1

((n-1) S^2 / \chi^2_{0.1/2}) < \sigma^2 < ((n-1) S^2 / \chi^2_{1 - 0.1/2} )
(( 7-1 ) \, 2.07 / 12.5916 ) < \sigma^2 < ((7-1)\, 2.07 / 1.6354 )
\chi^2 (0.1/2, 7 - 1 ) = 12.5916
\chi^2 (1 - 0.1/2, 7 - 1) ) = 1.6354
Lower Limit = 0.9932
Upper Limit = 2.7558
90% Confidence interval is ( 0.9932 , 2.7558 )
( 0.9932 < σ < 2.7558 )

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