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Vs is set to a sine function with a peak-to-peak voltage of 9.5V. The offset is 0. Here you can see that a DMM has been conne

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Answer

Given that

Vs = 9.5Vp-p

We know that Vrms VP-P 2V2

Then Vs = 3.359V

Also given that the input resistance is 15M2

By using Kirchoffs voltage law,

we get the KVL for the given loop is:

-Vs +501 + 15 Mi = 0

3.359 i= 15000050

i=2.239 + 10-7

Now,the voltage across the Voltmeter is

Vym = 15M * 2.239 * 10-7

Vym = 3.359V

So,when the DMM is Voltmeter the Voltage value is 3.359V

Simulation For confirmation

- х E Design 1 - Multisim - [Design1 *] Eile Edit View Place MCU Simulate Transfer Tools Reports Options Window Help --- In-U

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