Question

(5pts) 11. A 0.5V peak-to-peak 1kHz sine wave with a 100mV DC offset is provided as the input into a non- inverting operational amplifier with a gain of 20. If the output of the op-amp is read using an oscilloscope with AC coupling, then the value is close to a. 2V DC b. 2V peak-to-peak 1kHz sine wave c. 10V peak-to-peak 1kHz sine wave with 2V DC offset d. 10V peak-to-peak 1kHz sine wave only (5pts) 12. Which of the following statements is NOT true concerning operational amplifier? a. Op amps have a high input impedance so that the input current is ideally zero b. Op amps have high internal gains c. Op amps have high output impedance d. Op amps need both positive and negative voltage sources to work properly (5pts) 13. When reducing the capacitance value of the circuits shown below, then 5.1 k 2 M + + V (t) 0.01 uF V.(t) a. the offset (break) frequency will reduce b. the offset (break) frequency will increase c. the offset (break) frequency will remain the same d. the circuits will become a highpass filter

Answer 1

Il. If the Oscilloscopeis operating in ac Coupling Mode then it block the De components, for input 0.5 V peak to peak Vo = 20 Vo= 10 V vin Peakto peak of 1 kH3 sine wave Hence option is, is correct 12. of- Amp has low out put impedance and High input impedance, Hence option & i8 Correct. 5.1kH3 13 . 't in 0.01MBT Vo Who Xc = o Vo = vin Xc = vo so it is Low pass filter

1 for me 2a RC value When we Reduce the capacitance is increses, then fc 1 fca نام۔ С. is CoRRecto Hence option one (1)