1) Calculate the ac emitter resistance r'e for the value of IE = 5.52 mA. (In...

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Question

1) Calculate the ac emitter resistance r'_e for the value of I_E = 5.52 mA. (In Ω)

2) Calculate the value of ac load resistance r_L. (In kΩ)

3) Calculate the voltage gain A_V.

4) Calculate the value of output voltage. (V_p-p)

Required information In the circuit below: Vin = 10 mVp-p, R2 = 2.2 k12, R1 = 15 k12, Vcc = 21 V, RC = 3 k12, B = 100, RE = 3

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Answer 1

Answer #1

( U emitter resistance VT IE re V = 25mv If = 5.52mA 25x03 re 3 .5.52x10 re =4.5801 (8) AC equivalent Circuit Capacitors are

0 Ac load resistance. Y Re //RL V = 3kull 3ku/16 6.2kn V = 3x6.2 3+6.2 ņ = 2.02 kn 3 Voltage gain Vout -gm Voe (Re/lR) that V

218-59 Xios Av = gm = 218 .5.9 malu. -gm.(Rellow) Av = 441-93 v/v 3 2.02 x 10 ( 4 ) output Vol Hage Vout Av Vin Vin tomVp-p.

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Answer 2

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