Suppose a random variable has the normal distribution such that X∼(82,4.8)X∼(82,4.8). What value of the random variable cuts the bottom 10%? Give your answer to 4 decimal places.
Given that,
X∼(=
82,
= 4.8)
Therefore,
Let 'a' be the value which cuts the bottom 10%.
So, by problem,
(10% = 0.10)
The value which cuts the bottom 10% is 75.856. (Answer)
z table :
Suppose a random variable has the normal distribution such that X∼(82,4.8)X∼(82,4.8). What value of the random...
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