Question

4) If the 450 g tetherball is moving around the pole horizontally at an angle of 0 = 25°, what is the constant speed of the tetherball? B 1.S m

Answer 1

given

m=450 g

L=1.8 m

so radius of circle is

r=L sin Θ=1.8sin(25)

as we know,

$\small \\\\\text{For equilibrium condtion} \\\\F_x=\frac{mv^2}{r} \\\\T_{AB}sin(\theta)=\frac{mv^2}{1.8sin(25)} \\\\\frac{mg}{cos(\theta)}*sin(\theta)=\frac{mv^2}{1.8sin(25)} \\\\gtan(25)=\frac{v^2}{1.8*sin(25)} \\\\v^2=1.8g*tan(25)sin(25) \\\\v^2=1.8*9.81*tan(25)*sin(25) \\\\v=1.8654 \ m/s$

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