Question

A 12.0-V battery is connected into a series circuit containing a 15.0-22 resistor and a 2.20-H inductor. (a) In what time interval will the current reach 50.0% of its final value? (b) In what time interval will the current reach 90.0% of its final value? Step 1 The time constant for the circuit is defined to be r = L/R. This means that at time t = T, the current will reach 1 - 1/8 = 63% of its final value as shown in the graph. The time interval to reach 50% of Imax will be slightly less than the time constant, and the time interval to reach 90% of Imax will be about 2.57. زفة بع|ت 0.682 Step 2 The precise time intervals can be found from the equation for current as a function of time by substituting the time constant found from the inductance and resistance in the circuit. Step 3 At time t after connecting the circuit, we have the following equation for the current as a function of time. 8(1 - -/) I(C) - R

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Answer 1

.Cl-e-th) 6) Similarly for current to for current to reach 90% reach 90% of its final value, > e-tha=0.1 -t = m(od WHO 0.1467 t=-0.1467X (-2-303) og &t=0.3378 sec =>