Question

QUESTION ONE gw constitrat a) State Daltons law of partial pressures be taken to occupy the entre vchure. (2 marks) b) When

Part 3 is the total cooling load at the bottom

0 0
Add a comment Improve this question Transcribed image text
Answer #1

a) Dalton's law:
For a non reacting mixture of gasses Dalton law states that the total pressure exerted by the mixture is equal to the sum of partial pressure of individual gasses.

Thus can be written as
P = p1+p2+p3+p4....
Here P = total pressure of mixture. And p1 ,p2 ,p3 ,p4 etc are partial pressure of individual gasses.

I have explained throuly from basics hope you will understand easily please upvote it your positive reviews are motivates us. Thank you

Add a comment
Know the answer?
Add Answer to:
Part 3 is the total cooling load at the bottom QUESTION ONE gw constitrat a) State...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • QUESTION ONE gw constitrat a) State Dalton's law of partial pressures be taken to occupy the...

    QUESTION ONE gw constitrat a) State Dalton's law of partial pressures be taken to occupy the entre vchure. (2 marks) b) When are the dry-bulb and dew temperatures identical? (2 marks) c) Define the dew point temperature. (2 marks) The reaperture d) Moist air at 20°C, 1 bar, 43% relative humidity and a volumetric flow rate of 900 m/h enters a control volume at steady state and flows along a surface maintained at 65 °C, through which heat transfer occurs....

  • Moist air at 20°C, 1 atm, and 43% relative humidity and a volumetric flow rate of...

    Moist air at 20°C, 1 atm, and 43% relative humidity and a volumetric flow rate of 900 m/hrs. enters a control volume at steady state and flow along a surface maintained at 65° C, through which heat transfer occurs. Liquid water at 20° C is injected at a rate of 5 kg/hr and evaporates into flowing stream. For the control volume, Wev =0, and kinetic and potential energy effects are negligible. Moist air exits at 32°C, 1 atm. (a) draw...

  • Moist air at 20° c, 1 atm, and 43% relative humidity and a volumetric flow rate...

    Moist air at 20° c, 1 atm, and 43% relative humidity and a volumetric flow rate of 900 m/hrs. enters a control volume at steady state and flow along a surface maintained at 65 C, through which heat transfer occurs. Liquid water at 20" C is injected at a rate of 5 kg/hr and evaporates into flowing stream. For the control volume, Wa=0, and kinetic and potential energy effects are negligible. Moist air exits at 32c, 1 atm, (a) draw...

  • Moist air at 20°C, 1 atm, and 43% relative humidity and a volumetric flow rate of...

    Moist air at 20°C, 1 atm, and 43% relative humidity and a volumetric flow rate of 900 m²/hrs. enters a control volume at steady state and flow along a surface maintained at 65°C, through which heat transfer occurs. Liquid water at 20°C is injected at a rate of 5 kg/hr and evaporates into flowing stream. For the control volume, Wev=0, and kinetic and potential energy effects are negligible. Moist air exits at 32°C, 1 atm. (a) draw the system schematic...

  • use engineering methodology and show units calculations please B5. (15%) (Show all your calculation steps.) Moist...

    use engineering methodology and show units calculations please B5. (15%) (Show all your calculation steps.) Moist air at 20°C, 1 atm, and 43% relative humidity and a volumetric flow rate of 900 m3/hrs. enters a control volume at steady state and flow along a surface maintained at 65° C, through which heat transfer occurs. Liquid water at 20° C is injected at a rate of 5 kg/hr and evaporates into flowing stream. For the control volume, Wex=0, and kinetic and...

  • a) Define relative humidity (2 marks) b) Describe the relation between relative humidity, the capacity of...

    a) Define relative humidity (2 marks) b) Describe the relation between relative humidity, the capacity of air to hold moisture a ambient temperature. (2 marks) c) Moist air at 22°C and a wet bulb temperature of 9°C enters a steam spray humidifier. The mass flow of the dry air is 90 kg/min. Saturated water vapor at 110 °C is injected into the mixture at a rate of 52 kg/hr. There is no heat transfer with the surroundings, and the pressure...

  • QUESTION 1 [15 marks] Due: 5 August 2020 An air conditioner operating at steady state takes...

    QUESTION 1 [15 marks] Due: 5 August 2020 An air conditioner operating at steady state takes in moist air at 28°C, 1 atm and 70% relative humidity. The moist air first passes over a cooling coil in the dehumidifier unit and some water vapor is condensed. The rate of heat transfer between the moist air and the cooling coil is 38.69 kW. Both saturated moist air and condensate streams exit the dehumidifier unit at the same temperature. The moist air...

  • The atmospheric air 32 °C dry bulb temperature and 70% relative humidity supplied to the cooling...

    The atmospheric air 32 °C dry bulb temperature and 70% relative humidity supplied to the cooling coil at a rate of 45m3/min. The air cooling to the saturated state and leaving at a temperature of 16 °C. Determine: a- Specific humidity at each state. b- Wet bulb and dew point temperatures at the final state c- Final relative humidity. d- Mass of water condensed. e- Rate of heat removed from the air in kW. f- Show the process on Psychrometric...

  • Name: QUESTION 1 [25 Points] Moist air enters an air conditioning system at a dry bulb...

    Name: QUESTION 1 [25 Points] Moist air enters an air conditioning system at a dry bulb temperature T., 30 'C and relative humidity фі80% and exits at a dry bulb temperature T2 179C and relative humidity ф2.50% as shown in the figure below. The condensate exits the system at 15 °C. The mass flow rate of the dry air is 2.5 kg/s. Assume the air is at atmospheric pressure P-101.3 kPa. Cooling coils T-17 C 0-50 % Pp:-6.282 kPa Ti-30...

  • Air at 95°F, 1 atm, and 10% relative humidity enters an evaporative cooler operating at steady...

    Air at 95°F, 1 atm, and 10% relative humidity enters an evaporative cooler operating at steady state. The volumetric flow rate of the incoming air is 895 ft3/min. Liquid water at 68°F enters the cooler and fully evaporates. Moist air exits the cooler at 70°F, 1 atm. There is no significant heat transfer between the device and its surroundings and kinetic and potential energy effects can be neglected. a)Determine the mass flow rate of the dry air in lb(dry air)/min....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT