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1. Find the values of K and a for the system shown if the closed-loop response has a 0.12 second settling time and a 20% over

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Answer #1

Given • Settling time, ts = 0.12 sec • Overshoot, Mp = 20% = 0.2 R(S) E(S) C(s) K s(s + a) (sro = The transfer function for t

Percent Overshoot: πξ %Mp - 100 * e 1 - ξ2, πξ 20 = 100 και e ξ = 0.456 Settling Time: Ts: 4 For 2% error, TS - ξω, 4 0.12 0.

The general equation for a second order system with unit step input is, wn? = (2) C(s) R(S) s2 + (2Ęwn) s + wn? Comparing equ

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