Let A be the event that a person was wearing a seatbelt
P(A) = P()
probability=number of favorable outcomes./Total outcomes
number of favorable outcomes.=Number of person was wearing a seatbelt =412882
Total outcomes=total seat b person was wearing a seatbeltelt=577003
P(A)=412882/577003=0.7156
#probability of person was wearing a seatbelt is 0.7156
step by step This table is based on records of "injury" motor vehicle accidents where the...
Question 7 0/2 pts This table is based on records of "injury" motor vehicle accidents where the occupants either sustained a nonfatal injury or at least one of the occupants sustained a fatal injury. The data were compiled by a State Highway Safety and Motor Vehicles Office. If we randomly select someone injured in a motor vehicle accident, what is the probability that person was wearing a seatbelt and was not fatally injured? Enter your answer as a decimal and...
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