Question

4. (-14 Points) DETAILS SERCP11 18.4.P.018. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHE Consider the following figure. Note: The currents are not necessarily in the direction shown. (Assume R-32.00, Ry - 4.0, and V-33) R w w 24 W R (a) Find the current in each resister of the figure above by using the rules for resistors in series and parallel 4.00 32.00 24 А (b) write three independent equations for the three currents using Kirchoff's laws: one with the moderule; a second using the loop rule through the battery, the 40-resister and the 24.0-0 resistor, and the third using the loop rule through the 2.0 and 240-resistors, Selve to check the answers found in part(s) (submit a file with a maximum size of 1 HD) Cholested This was not been red yel Show My Work

Answer 1

Answer . Given : V 33 V: Ri: 3212 R₂ 4.12 Ri I 241 124. R2 м. Iz . V a) Here R, and 242 are parallel 24 + R, 24 24 x Ri. 24 + 32 - + R R 24 * 32 R 24 x 32 13-12 56 งไร การ And R is in series with R2 R 'eff R + R₂ 13.7 + 4 17.112 33 Total current: I Reff 17.7 1-864 A The same Current will flow through R I 2 = 1.864 A.

Voltage drop across R, V, IR2 V, 1.864 X 4 7. 456 V N-V2 Remaining voltage ; V = 33.0 - 7: 456. 25.544 V The across R same voltage will be there and 242 Iz 25.544 0-198 A 32 I 24 25.544 1.06 A 24 b ) From the Circuit ; I 2 T, + Izu ( kivehofs's CUTY OF lau) IR + I₂ R2 V 2 32 I, + HIZ: 33 Similarly : I ₂ R₂ + 124 x 2 4 1 33 4 I 2 + 24 I 24 33 3 from equation = I24 12-1 ☺ -> HI2 + 24 C I2 - 7,), 33 G 28 I₂ 24 I 33.

1 x 8) 7. 224T + 2812 231. (-) - 241 33 + 28 J2 H २481 198 198 248 0.798A In equation 4 → 33 28 12 24x 0.198 26 12 33 + ( 24 X ७.798) - 28 1 %3D 52. 152 T 52.152 28 1-862 A 24 - 2 - 1. 10862 0.198 V |• 064 A 2