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22) Runners World magazine wanted to find out what the average 5k running time was for recreational runners. To estimate thi

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Answer #1

Solution :

Given that,

t\alpha /2,df = 1.998

Margin of error = E = t\alpha/2,df * (s /\sqrtn)

= 1.998 * (5 / \sqrt 64)

Margin of error = E = 1.2

The 95% confidence interval estimate of the population mean is,

\bar x - E < \mu < \bar x + E

28 - 1.2 < \mu < 28 + 1.2

26.8 < \mu < 29.2

(26.8 , 29.2)

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