Question

A battery having an emf of 9.03 V delivers 120 mA when connected to a 62.5 load. Determine the internal resistance of e battery Need Help? Read [-720 Points] DETAILS SERCP11 18.3.P.006. Three 6.2 resistors are connected in series with a 2.0 V battery. Find the following. (a) the equivalent resistance of the circuit (b) the current in each resistor (c) Repeat for the case in which all three resistors are connected in parallel across the battery. equivalent resistance current in each resistor Need Help? Read [-720 Points] DETAILS SERCP11 18.4.P.018. Consider the following figure. Note: The currents are not necessarily in the direction shown. (ASUMAR- 24.0, R2 - 5.00, and V-30V) 24 (a) Find the current in each resistor of the figure above by using the rules for resistors in series and parallel 5.00 TA A (b) write three independent equations for the three currents using Kirchoff's laws one with the nade rule; a second using the loop rule through the battery, the 5.0-resistor, and the 24.0-resistor, and the third using the loop rule through the 24.0-1 and 24.0-2 resistors Choose fic No flc chosen This answer has not haan gradadyat

Answer 1

> - AV I (R+3) - r = V-TR 9.03 – 0.12(62.5) 2 0.12 9 = 12.751 Ave 22v Three resistor connected in series R = RAR+ R3 = 3R = 3 (6.2) equ AV 22 AV-IR Peru - I 18.6 Since in series I' lame = 3 (6.2) = 18660 ♡ El 18 A b ber → I-1.18 A When resistors connected in parallel, Peque = 2.07 u 6.2 3 Voltage acro) each sexigta il v= 22v. 22 3.554 Ir / 6.2